The formula

Faraday's law for an N-turn coil
ε = -N·ΔΦ / Δt
Instantaneous form
ε = -N·dΦ/dt
Magnetic flux through a flat loop in a uniform field
Φ = BA·cos θ

What the symbols mean

SymbolMeaningUnit
εInduced electromotive forceV
NNumber of turns in the coildimensionless
ΦMagnetic flux through one turnWb (1 Wb = 1 T·m²)
ΔtTime over which the flux changess
BMagnetic field strengthT
AArea of the loop
θAngle between the field and the normal to the loopdegrees or radians

When it applies

  • Anything that changes the flux works: a changing field strength, a changing loop area, or a loop rotating in a steady field.
  • A steady field through a stationary loop induces nothing at all. Only the rate of change matters.
  • Use the magnitude to size the emf, then apply Lenz's law separately to get the direction of the induced current.

Worked example

Problem. A 200-turn coil of area 0.010 m² sits with its plane perpendicular to a magnetic field. The field rises steadily from 0.20 T to 0.60 T over 0.50 s. What emf is induced?

  1. The field is perpendicular to the plane of the coil, so it is parallel to the normal, θ = 0 and Φ = BA.
  2. Flux change per turn: ΔΦ = A·ΔB = (0.010 m²)(0.60 - 0.20 T) = 4.0 × 10⁻³ Wb.
  3. Faraday's law, taking magnitudes: |ε| = N·ΔΦ / Δt = (200)(4.0 × 10⁻³) / 0.50 s.
  4. |ε| = 0.80 / 0.50 = 1.6 V.
  5. By Lenz's law the induced current circulates in whichever sense makes its own magnetic field point opposite to the growing applied field inside the coil.

Answer. 1.6 V while the field is changing, dropping to zero the moment the field steadies.

Common mistakes

  • Leaving out the number of turns. A 200-turn coil gives 200 times the emf of a single loop.
  • Measuring θ from the plane of the loop instead of from its normal, which swaps the sine and the cosine.
  • Thinking a strong field alone induces an emf. Only a changing flux does.
  • Reading the minus sign as a negative voltage. It encodes direction, not a sign on the magnitude.

Related formulas

Sources