The formula

From linear speed
F_c = mv² / r
From angular speed
F_c = mrω²
Centripetal acceleration
a_c = v² / r
Speed from the period of one revolution
v = 2πr / T

What the symbols mean

SymbolMeaningUnit
F_cNet inward force required for the circular pathN
mMass of the objectkg
vSpeed along the circular pathm/s
rRadius of the path, measured to the centerm
ωAngular speedrad/s
a_cCentripetal acceleration, directed toward the centerm/s²
TPeriod, the time for one full revolutions
πRatio of a circle's circumference to its diameter3.1416 (dimensionless)

When it applies

  • Uniform circular motion, or the instantaneous inward direction at any point on a curved path.
  • Work out which real force supplies it before you use the formula. Adding F_c to a free-body diagram alongside that force counts it twice.
  • r is the radius of the circular path, measured from the center, not the diameter.

Worked example

Problem. A 0.20 kg puck on the end of a 0.75 m string travels in a circle on a frictionless horizontal table at 3.0 m/s. How hard does the string pull?

  1. The string tension is the only horizontal force, so it supplies the entire inward force: T = F_c.
  2. Substitute into F_c = mv² / r: F_c = (0.20 kg)(3.0 m/s)² / 0.75 m.
  3. (3.0)² = 9.0, so the numerator is (0.20)(9.0) = 1.8.
  4. Divide: F_c = 1.8 / 0.75 = 2.4 N.

Answer. The string pulls inward with 2.4 N. Doubling the speed to 6.0 m/s would need 9.6 N, four times as much.

Common mistakes

  • Drawing an outward centrifugal force on a free-body diagram. In an inertial frame no such force acts on the object.
  • Adding F_c as an extra force alongside the tension or friction that is actually producing it.
  • Using the diameter of the circle in place of the radius.
  • Underestimating how fast the requirement grows. Speed is squared, so a small increase in speed needs a large increase in force.

Related formulas

Sources