The formula

System of point masses
I = Σ mᵢrᵢ²
Solid disk or cylinder about its central axis
I = ½mR²
Thin rod about an axis through its center
I = (1/12)mL²
Parallel-axis theorem
I = I_cm + md²

What the symbols mean

SymbolMeaningUnit
IMoment of inertia about the stated axiskg·m²
mᵢMass of one point particle in the systemkg
rᵢDistance of that particle from the axism
mTotal mass of the bodykg
RRadius of the disk or cylinderm
LLength of the rodm
I_cmMoment of inertia about a parallel axis through the center of masskg·m²
dDistance between the two parallel axesm

When it applies

  • You need the rotational counterpart of mass, either for Στ = Iα or for rotational kinetic energy K = ½Iω².
  • Name the axis before quoting a value. A rod spun about its center has one quarter the moment of inertia of the same rod spun about one end.
  • Use the parallel-axis theorem only when the new axis is parallel to one through the center of mass, a distance d away.

Worked example

Problem. A solid disk of mass 2.5 kg and radius 0.20 m spins about its central axis. Find its moment of inertia, then the angular acceleration a 0.75 N·m torque would produce.

  1. For a solid disk about its central axis, I = ½mR² = ½(2.5 kg)(0.20 m)².
  2. (0.20 m)² = 0.040 m², so I = (0.5)(2.5)(0.040) = 0.050 kg·m².
  3. Apply the rotational form of Newton's second law: α = τ / I = 0.75 N·m / 0.050 kg·m².
  4. α = 15 rad/s².

Answer. I = 0.050 kg·m², and the disk gains angular speed at 15 rad/s².

Common mistakes

  • Quoting a moment of inertia without naming the axis, which leaves the number meaningless.
  • Forgetting to square the radius or the length, which is where most of the arithmetic slips happen.
  • Using the parallel-axis theorem from an axis that is not through the center of mass. It only works starting from the center-of-mass axis.
  • Adding moments of inertia taken about different axes. They add only when they share the same axis.

Related formulas

Sources